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28. Implement strStr()Leetcode 2021. 5. 25. 15:57
Implement strStr().
Return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.
Clarification:
What should we return when needle is an empty string? This is a great question to ask during an interview.
For the purpose of this problem, we will return 0 when needle is an empty string. This is consistent to C's strstr() and Java's indexOf().
Example 1:
Input: haystack = "hello", needle = "ll" Output: 2
Example 2:
Input: haystack = "aaaaa", needle = "bba" Output: -1
Example 3:
Input: haystack = "", needle = "" Output: 0
Constraints:
- 0 <= haystack.length, needle.length <= 5 * 104
- haystack and needle consist of only lower-case English characters.
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class Solution(object): def strStr(self, haystack, needle): """ :type haystack: str :type needle: str :rtype: int """ if needle == "": return 0 try: idx = haystack.index(needle, 0, len(haystack)) return idx except ValueError: return -1
- 정규식 find/match/search로 풀려고 했으나, string에 좋은 method가 있어서 쉽게 풀었다.
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