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  • 28. Implement strStr()
    Leetcode 2021. 5. 25. 15:57

    Implement strStr().

    Return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.

    Clarification:

    What should we return when needle is an empty string? This is a great question to ask during an interview.

    For the purpose of this problem, we will return 0 when needle is an empty string. This is consistent to C's strstr() and Java's indexOf().

     

    Example 1:

    Input: haystack = "hello", needle = "ll" Output: 2

    Example 2:

    Input: haystack = "aaaaa", needle = "bba" Output: -1

    Example 3:

    Input: haystack = "", needle = "" Output: 0

     

    Constraints:

    • 0 <= haystack.length, needle.length <= 5 * 104
    • haystack and needle consist of only lower-case English characters.
    • class Solution(object):
          def strStr(self, haystack, needle):
              """
              :type haystack: str
              :type needle: str
              :rtype: int
              """
              if needle == "":
                  return 0
              
              try:
                  idx = haystack.index(needle, 0, len(haystack))
                  return idx
              except ValueError:
                  return -1

    - 정규식 find/match/search로 풀려고 했으나, string에 좋은 method가 있어서 쉽게 풀었다. 

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